sub list (subList)
(subList list1 list2) means that list1 is a
sublist of list2, i.e. every element of list1 is an element of list2 and
the elements that are common to both Lists have the same order in both
Lists.
Ontology
SUMO / BASE-ONTOLOGYClass(es)
Subrelation(s)
initial list
Coordinate term(s)
arc weight
authors
before or equal
causes
causes subclass
citizen
closed on
connected
contains information
cooccur
copy
date
decreases likelihood
developmental form
disjoint
distributes
documentation
duration
earlier
editor
element
employs
equal
equivalence relation on
exploits
expressed in language
faces
family relation
finishes
frequency
graph part
greater than
greater than or equal to
has purpose
has skill
holds during
holds obligation
holds right
hole
identity element
in list
in scope of interest
increases likelihood
independent probability
inhabits
inhibits
initial list
instance
inverse
irreflexive on
larger
less than
less than or equal to
located
material
measure
meets temporally
modal attribute
overlaps temporally
parent
part
partial ordering on
partly located
path length
possesses
precondition
prevents
property
publishes
range
range subclass
refers
reflexive on
related internal concept
sibling
smaller
starts
sub attribute
sub collection
sub graph
sub process
sub proposition
subclass
subrelation
subsumes content class
subsumes content instance
successor attribute
successor attribute closure
temporal part
time
total ordering on
trichotomizing on
uses
valence
version
Type restrictions
subList(list, list)
Axioms (2)
- if list1 is a sublist of list2,
- then for all item holds: if item is a member of list1, then item is a member of list2
.
(=>
(subList ?LIST1 ?LIST2)
(forall
(?ITEM)
(=>
(inList ?ITEM ?LIST1)
(inList ?ITEM ?LIST2))))
- if list1 is a sublist of list2,
- then there exists number3 so that for all item holds: if item is a member of list1, then there exist number1,number2 so that "number1th element of list1" is equal to item and "number2th element of list2" is equal to item and number2 is equal to "(number1+number3)"
.
(=>
(subList ?LIST1 ?LIST2)
(exists
(?NUMBER3)
(forall
(?ITEM)
(=>
(inList ?ITEM ?LIST1)
(exists
(?NUMBER1 ?NUMBER2)
(and
(equal
(ListOrderFn ?LIST1 ?NUMBER1)
?ITEM)
(equal
(ListOrderFn ?LIST2 ?NUMBER2)
?ITEM)
(equal
?NUMBER2
(AdditionFn ?NUMBER1 ?NUMBER3))))))))